didn't knkow this was an arguement, but since this is the internet, i guess somebody will always be able to find one whether or not one is going on.
This is gathering facts. There are no arguments with the absolute.
and then there is a gaping flaw in your logic: 14.6 afr has nothing to do with air pressure. nothing to do with vacuum.
Sure it does. You sound like a 'more air' kind of guy, I'm the 'same air' kind of guy.
Take a tire pump. That has a leather gasket soaked in oil, looks like a cup when you bolt down the center. It rides in a long tube. There is a hole at the top. Call that the 14.7 hole. There's a hole at the bottom. Call that the compression or pressure side like an engine.
The question to you is: What is the air pressure each time you lift the rod from the bottom?
The next question is: What is the pressure on the other side, you stop at TDC? Man, if you do not see a constant 14.7 on both sides, you are lost with the very first step of FI theory. Can you say stoic? 1 atm? 1ATMO? No sensor is out of spec if the very first number is? ______ Fill in the blank?
I can lift at high rpm and have a 12:1 afr, 13:1 afr, or 17: afr, it all depends on how much air is entering the engine in relation to the amount of fuel I have set to be injected.
See what you just said? Amount of fuel entering first is the displacer. We are sucking in 14.7 is the constant. Our ratio is now the AFR. How much of a bubble could get in fighting a liquid that is already there? 14.7 is still the number when closed. Upon fire is the AFRatio exposed. That's why you begin and end with the 760mmHG as your base number be it in open loop, a main sensor fails, the ECU begins to calc in a limp condition. This is the calc'd number all in a safe, won't harm the engine, 'we take measures.' Get it yet?
afr is air-to-fuel ratio. at a stoichiometric blend, there will be about 14.6 units of air (by mass) per 1 unit of fuel (also by mass). doesn't matter the air pressure.
Now you got it. How did you get there? The theory is as if you took a solid(crude), turned it into a liquid(gasoline), and now in theory, turn it into a single oxygen base back to... "You cannot create or destroy matter," so it is still a gas of what it began as. You sure are not breathing stoic we close the garage door and watch you breath the 1ATMO w/eng running.
an engine running at sea level at 14.6 afr will produce the same amount of power per unit of fuel burned if you move it to pikes peak where you have about 60% of the oxygen density. it will produce less power due to less oxygen available, therefore less fuel being burned, but you would still have a stoich mix of 14.6:1 afr. if you added fuel and lowered the afr to a lesser number to match the atmospheric pressure value, you would be running quite rich.
hopefully that helps.
What you are saying is an engine running at sea level will make this much HP with this much air. Bring it up to pikes peak, you still close at 1 atm.
So, are we on the same page yet? 14.7 is the number no matter watt. Show me in that bicycle pump another number besides 14.7 on both sides is the same as saying, show me a different number than 14.7 at BDC of that engine. Because whatever momentum you think is following and will keep pushing a higher number when that piston is now moving up, show me that other number.
Now, do we understand the 1ATMO vs. AFR? And do we fire off every single fire with an AFR meter pegged at 14.6 from idle to WOT... yes or no? Is my engine lying to you or are you watching a timing of rpm vs. who enters first [under what vacuum vs. sensor] that compensates all that detonation and vacuum advance curve is the ignition too that makes or breaks ratio?